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Known Quantities: Inductor current initial condition (current at t = 0); inductance value Find: Energy stored in inductor Schematics, Diagrams, Circuits, and Given Data: L = 10 mH; iL = I0 = 8 A Analysis:

187 156 107 126

A useful analogy can be made between the ow of electrical current through electrical components and the ow of incompressible uids (eg, water, oil) through hydraulic components The analogy starts with the observation that the volume ow rate of a uid in a pipe is analogous to current ow in a conductor Similarly, the pressure drop across the pipe is analogous to the voltage drop across a resistor Figure 413 depicts this relationship graphically The uid resistance presented by the pipe to the uid ow is analogous to an electrical resistance: The pressure difference between the two ends of the pipe, (P1 P2 ), causes uid ow, qf , much like a potential difference across a resistor forces a current ow: 1 qf = (p1 p2 ) Rf i= 1 (v1 v2 ) R

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In this exercise, you will create a new web application that will later become a web-based, bug-reporting application. Follow these steps to complete the exercise: 1. Create a new ASP.NET website with a location set to c:\WebSites\BugReporter (again, see Figure 9-11). This will create a new folder and add a new default web form called Default.aspx. A window with code that looks like Listing 9-4 should appear. This web form will become the menu page for your website. 2. Add a heading and two buttons to the body of the document by typing code into the web page, as shown here: <form id="form1" runat="server"> <div> <h1>Bug Reports Web Site</h1> <asp:Button ID="btnReportBug" runat="server" Text="Report a Bug" Width="226px" /> <p /> <asp:Button ID="btnViewBugs" runat="server" Text="View Reported Bugs" Width="226px" /> </div> </form> 3. At the bottom of Visual Studio, you will see two buttons labeled Design and Source. You are looking at the Source option now; switch to the Design option by clicking the word Design. You should see a heading and the two buttons (see Figure 9-14).

p2 + p _

The analogy between electrical and hydraulic circuits can also be extended to include energy storage effects corresponding to capacitance and inductance If the uid enters a vessel that has some elasticity (compressibility), energy can be stored in the expansion and contraction of the vessel walls (if this reminds you of a mechanical spring, you are absolutely right!) This phenomenon gives rise to a uid capacitance effect very similar to the electrical capacitance phenomenon we have just introduced Energy is stored in the compression and expansion of the gas; this form of energy storage is of the potential energy type Figure 414 depicts a so-called gas bag accumulator, which consists of a two-chamber arrangement that permits uid to displace a membrane separating the incompressible uid from a compressible uid (eg, air) If, for a moment, we imagine that the reference pressure, p2 , is zero (think of this as a ground or reference pressure), and that the voltage is the reference or ground voltage, we can create an analogy between an electrical capacitor and a uid capacitor (the gas-bag accumulator) as shown in Figure 414 qf = Cf i=C d p dp1 = Cf dt dt

d v dv1 =C dt dt The nal element in the analogy is the so-called uid inertance parameter, which is analogous to inductance in the electrical circuit Fluid inertance, as the name suggests, is caused by the inertial properties, ie, the mass, of the uid in motion As you know from physics, a particle in motion has kinetic energy associated with it; uid in motion consists of a collection of particles, and it also therefore must have kinetic energy storage properties If you wish to experience the kinetic energy contained in a uid in motion, all you have to do is hold a re hose and experience the reaction force caused by the uid in motion on your body! Figure 415 depicts the analogy between electrical inductance and uid inertance These analogies and the energy equations are summarized in Table 42 p = p1 p2 = If v = v1 v2 = L dqf dt

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156 133 100 107

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